36t^2-48-12t=0

Solution for 36t^2-48-12t=0 equation:

36t^2-48-12t=0

a = 36; b = -12; c = -48;
Δ = b2-4ac
Δ = -122-4·36·(-48)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-84}{2*36}=\frac{-72}{72}
=-1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+84}{2*36}=\frac{96}{72}
=1+1/3
$